High Reasoning

o3-mini

OpenAI o3-mini is the most cost-efficient reasoning model, excelling in STEM tasks like coding, math, and science with low latency, tool integration, and three adjustable reasoning levels. Unlock powerful, precise AI for high-volume applications at a fraction of the cost of previous models.

200k Context

High Intelligence

Oct '23 Knowledge

Available for Chat, Vision, and File Uploads.

Performance Benchmarks

MMLU

77.0%

HumanEval

95.1%

GPQA

77.0%

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Why use o3-mini?

Adaptive Reasoning

Scales intelligence dynamically with user-controlled "Thinking Effort" toggles (low, medium, high) for balancing speed and depth on complex tasks like physics proofs or coding

Elite Coding Performance

Excels in coding benchmarks, achieving top Elo scores (e.g., 2727 on Codeforces), autonomous debugging, and full system architecture design

STEM Excellence

Matches or surpasses prior models in math, science, and technical reasoning with cost-efficient speed, structured outputs, and function calling

Capability Examples

Math Problem Solving

Solve this AIME-level math problem: Find the number of positive integers n ≤ 1000 such that the equation x^2 + n x + (n+1) = 0 has integer roots.

The quadratic equation x² + n x + (n+1) = 0 has discriminant D = n² - 4(n+1) = n² - 4n - 4. For integer roots, D must be a perfect square k² where k is a non-negative integer, and roots (-n ± k)/2 are integers. Solving n² - 4n - 4 = k² leads to (n-2)² - k² = 8, or (n-2 - k)(n-2 + k) = 8. Factoring pairs of 8 yields 7 solutions for n ≤ 1000: n=1,3,6,10,20,36,100. There are 7 such n.

Coding Debug

Debug this Python code with a race condition: def increment_shared(counter): global shared; shared += 1; [Run 1000 threads calling increment_shared(0)]. Why is shared not 1000?

Race condition: Multiple threads read/modify shared simultaneously without synchronization, causing lost updates. Fix with threading.Lock: import threading; lock = threading.Lock(); def increment_shared(): global shared; with lock: shared += 1. This ensures atomic increments, resulting in shared == 1000 reliably.

How to use

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